Game of Possibility Solution

 

Problem

In the games played so far in the tournament, your team has earned $P$ points. To qualify for the semi-finals, you must collect a total of at least $Q$ points. You currently have $R$ games remaining in which you can earn $2$ points for a victory, $1$ points for a tie, and no points for a loss.

Is it possible that your team will make it to the semi-finals?

Input Format

• The first line will have the value $T$, which represents the number of testcases. Then come the testcases.
• Each testcase has a single line of input and three numbers $P, Q, R$.

Output Format

For each test case, output in a single line YES if your team can qualify for the semi-finals, or NO if not possible.

Because output is case insensitive, "yes", "Yes", "YEs", "no", "nO" - all such strings will be accepted.

Constraints

• $1 \leq T \leq 5000$
• $0 \leq P,Q,R \leq 1000$

Sample 1:

Input

Output

3
4 10 8
3 6 1 
4 8 2 

YES
NO
YES

Explanation:

Test Case $1$: There are still $8$ games available. If you win $2$ games, lose $4$ games, and draw the remaining $2$ games, you will have a total of $10$ points, demonstrating that it is achievable.

Test Case $2$: There is no way that you can qualify for the semi-finals.

Test Case $3$: You will have $8$ points if you win all of the remaining games. As a result, qualifying for the semi-finals is possible ($4 + 2*2 = 8$).

Program :

/* package codechef; // don't place package name! */

import java.util.*;

import java.lang.*;

import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */

class Codechef

{

public static void main (String[] args) throws java.lang.Exception

{

// your code goes here

int p,q,r,t,a;

        Scanner sc=new Scanner(System.in);

        t=sc.nextInt();

        while(t-->0){

            p=sc.nextInt();

            q=sc.nextInt();

            r=sc.nextInt();

            a=r*2;

            if(p+a>=q)

                System.out.println("YES");

            else

                System.out.println("NO");

        }

}

}